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#1045
Medium Database

Customers who bought all products

Database
63.7% acceptance
Feb 27, 2026
1122
95
Table: Customer +-------------+---------+ | Column Name | Type | +-------------+---------+ | customer_id | int | | product_key | int | +-------------+---------+ This table may contain duplicates rows. customer_id is not NULL. product_key is a foreign key (reference column) to Product table. Table: Product +-------------+---------+ | Column Name | Type | +-------------+---------+ | product_key | int | +-------------+---------+ product_key is the primary key (column with unique values) for this table. Write a solution to report the customer ids from the Customer table that bought all the products in the Product table. Return the result table in any order. The result format is in the following example.

Solution

SQL
LeetCode
solution.sql
#
# Table: Customer
# +-------------+---------+
# | Column Name | Type    |
# +-------------+---------+
# | customer_id | int     |
# | product_key | int     |
# +-------------+---------+
# This table may contain duplicates rows.
# customer_id is not NULL.
# product_key is a foreign key (reference column) to Product table.
# Table: Product
# +-------------+---------+
# | Column Name | Type    |
# +-------------+---------+
# | product_key | int     |
# +-------------+---------+
# product_key is the primary key (column with unique values) for this table.
# Write a solution to report the customer ids from the Customer table that bought all the products in the Product table.
# Return the result table in any order.
# The result format is in the following example.
# Example 1:
# Input:
# Customer table:
# +-------------+-------------+
# | customer_id | product_key |
# +-------------+-------------+
# | 1           | 5           |
# | 2           | 6           |
# | 3           | 5           |
# | 3           | 6           |
# | 1           | 6           |
# +-------------+-------------+
# Product table:
# +-------------+
# | product_key |
# +-------------+
# | 5           |
# | 6           |
# +-------------+
# Output:
# +-------------+
# | customer_id |
# +-------------+
# | 1           |
# | 3           |
# +-------------+
# Explanation:
# The customers who bought all the products (5 and 6) are customers with IDs 1 and 3.
#

# Write your MySQL query statement below

SELECT customer_id
FROM Customer
GROUP BY customer_id
HAVING COUNT(DISTINCT product_key) = (SELECT COUNT(*) FROM Product);