#1083
Easy Database Sales analysis ii
Database
50.1% acceptance
Mar 31, 2026
282
49
No description available.
Solution
Pandas
Time O(1)
Space O(1)
# Table: Product
#
# +--------------+---------+
# | Column Name | Type |
# +--------------+---------+
# | product_id | int |
# | product_name | varchar |
# | unit_price | int |
# +--------------+---------+
# product_id is the primary key (column with unique values) of this table.
# Each row of this table indicates the name and the price of each product.
#
# Table: Sales
#
# +-------------+---------+
# | Column Name | Type |
# +-------------+---------+
# | seller_id | int |
# | product_id | int |
# | buyer_id | int |
# | sale_date | date |
# | quantity | int |
# | price | int |
# +-------------+---------+
# This table might have repeated rows.
# product_id is a foreign key (reference column) to the Product table.
# buyer_id is never NULL.
# sale_date is never NULL.
# Each row of this table contains some information about one sale.
#
#
#
# Write a solution to report the buyers who have bought S8 but not iPhone. Note that S8 and iPhone are products presented in the Product table.
#
# Return the result table in any order.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Product table:
# +------------+--------------+------------+
# | product_id | product_name | unit_price |
# +------------+--------------+------------+
# | 1 | S8 | 1000 |
# | 2 | G4 | 800 |
# | 3 | iPhone | 1400 |
# +------------+--------------+------------+
# Sales table:
# +-----------+------------+----------+------------+----------+-------+
# | seller_id | product_id | buyer_id | sale_date | quantity | price |
# +-----------+------------+----------+------------+----------+-------+
# | 1 | 1 | 1 | 2019-01-21 | 2 | 2000 |
# | 1 | 2 | 2 | 2019-02-17 | 1 | 800 |
# | 2 | 1 | 3 | 2019-06-02 | 1 | 800 |
# | 3 | 3 | 3 | 2019-05-13 | 2 | 2800 |
# +-----------+------------+----------+------------+----------+-------+
# Output:
# +-------------+
# | buyer_id |
# +-------------+
# | 1 |
# +-------------+
# Explanation: The buyer with id 1 bought an S8 but did not buy an iPhone. The buyer with id 3 bought both.
import pandas as pd
def sales_analysis(product: pd.DataFrame, sales: pd.DataFrame) -> pd.DataFrame:
merged = sales.merge(product, on='product_id')
s8_buyers = set(merged[merged['product_name'] == 'S8']['buyer_id'])
iphone_buyers = set(merged[merged['product_name'] == 'iPhone']['buyer_id'])
result_ids = s8_buyers - iphone_buyers
return pd.DataFrame({'buyer_id': list(result_ids)})