#110
Easy Algorithms Balanced binary tree
Tree Depth-First Search Binary Tree
57.9% acceptance
Feb 27, 2026
12127
839
Given a binary tree, determine if it is height-balanced.
Solution
Rust
Time O(n)
Space O(n)
// Definition for a binary tree node.
// #[derive(Debug, PartialEq, Eq)]
// pub struct TreeNode {
// pub val: i32,
// pub left: Option<Rc<RefCell<TreeNode>>>,
// pub right: Option<Rc<RefCell<TreeNode>>>,
// }
//
// impl TreeNode {
// #[inline]
// pub fn new(val: i32) -> Self {
// TreeNode {
// val,
// left: None,
// right: None
// }
// }
// }
use std::rc::Rc;
use std::cell::RefCell;
impl Solution {
pub fn is_balanced(root: Option<Rc<RefCell<TreeNode>>>) -> bool {
fn height(node: Option<Rc<RefCell<TreeNode>>>) -> i32 {
match node {
None => 0,
Some(n) => {
let n_borrow = n.borrow();
let left_height = height(n_borrow.left.clone());
if left_height == -1 {
return -1;
}
let right_height = height(n_borrow.right.clone());
if right_height == -1 {
return -1;
}
if (left_height - right_height).abs() > 1 {
return -1;
}
1 + left_height.max(right_height)
}
}
}
height(root) != -1
}
}