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#1179
Easy Database

Reformat department table

Database
76.3% acceptance
Feb 27, 2026
845
640
Table: Department +-------------+---------+ | Column Name | Type | +-------------+---------+ | id | int | | revenue | int | | month | varchar | +-------------+---------+ In SQL,(id, month) is the primary key of this table. The table has information about the revenue of each department per month. The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]. Reformat the table such that there is a department id column and a revenue column for each month. Return the result table in any order. The result format is in the following example.

Solution

SQL
LeetCode
solution.sql
#
# Table: Department
# +-------------+---------+
# | Column Name | Type    |
# +-------------+---------+
# | id          | int     |
# | revenue     | int     |
# | month       | varchar |
# +-------------+---------+
# In SQL,(id, month) is the primary key of this table.
# The table has information about the revenue of each department per month.
# The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
# Reformat the table such that there is a department id column and a revenue column for each month.
# Return the result table in any order.
# The result format is in the following example.
# Example 1:
# Input:
# Department table:
# +------+---------+-------+
# | id   | revenue | month |
# +------+---------+-------+
# | 1    | 8000    | Jan   |
# | 2    | 9000    | Jan   |
# | 3    | 10000   | Feb   |
# | 1    | 7000    | Feb   |
# | 1    | 6000    | Mar   |
# +------+---------+-------+
# Output:
# +------+-------------+-------------+-------------+-----+-------------+
# | id   | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
# +------+-------------+-------------+-------------+-----+-------------+
# | 1    | 8000        | 7000        | 6000        | ... | null        |
# | 2    | 9000        | null        | null        | ... | null        |
# | 3    | null        | 10000       | null        | ... | null        |
# +------+-------------+-------------+-------------+-----+-------------+
# Explanation: The revenue from Apr to Dec is null.
# Note that the result table has 13 columns (1 for the department id + 12 for the months).
#

# Write your MySQL query statement below

SELECT id,
  SUM(CASE WHEN month = 'Jan' THEN revenue END) AS Jan_Revenue,
  SUM(CASE WHEN month = 'Feb' THEN revenue END) AS Feb_Revenue,
  SUM(CASE WHEN month = 'Mar' THEN revenue END) AS Mar_Revenue,
  SUM(CASE WHEN month = 'Apr' THEN revenue END) AS Apr_Revenue,
  SUM(CASE WHEN month = 'May' THEN revenue END) AS May_Revenue,
  SUM(CASE WHEN month = 'Jun' THEN revenue END) AS Jun_Revenue,
  SUM(CASE WHEN month = 'Jul' THEN revenue END) AS Jul_Revenue,
  SUM(CASE WHEN month = 'Aug' THEN revenue END) AS Aug_Revenue,
  SUM(CASE WHEN month = 'Sep' THEN revenue END) AS Sep_Revenue,
  SUM(CASE WHEN month = 'Oct' THEN revenue END) AS Oct_Revenue,
  SUM(CASE WHEN month = 'Nov' THEN revenue END) AS Nov_Revenue,
  SUM(CASE WHEN month = 'Dec' THEN revenue END) AS Dec_Revenue
FROM Department
GROUP BY id;