#1179
Easy Database Reformat department table
Database
76.3% acceptance
Feb 27, 2026
845
640
Table: Department
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| revenue | int |
| month | varchar |
+-------------+---------+
In SQL,(id, month) is the primary key of this table.
The table has information about the revenue of each department per month.
The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
Reformat the table such that there is a department id column and a revenue column for each month.
Return the result table in any order.
The result format is in the following example.
Solution
SQL
#
# Table: Department
# +-------------+---------+
# | Column Name | Type |
# +-------------+---------+
# | id | int |
# | revenue | int |
# | month | varchar |
# +-------------+---------+
# In SQL,(id, month) is the primary key of this table.
# The table has information about the revenue of each department per month.
# The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
# Reformat the table such that there is a department id column and a revenue column for each month.
# Return the result table in any order.
# The result format is in the following example.
# Example 1:
# Input:
# Department table:
# +------+---------+-------+
# | id | revenue | month |
# +------+---------+-------+
# | 1 | 8000 | Jan |
# | 2 | 9000 | Jan |
# | 3 | 10000 | Feb |
# | 1 | 7000 | Feb |
# | 1 | 6000 | Mar |
# +------+---------+-------+
# Output:
# +------+-------------+-------------+-------------+-----+-------------+
# | id | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
# +------+-------------+-------------+-------------+-----+-------------+
# | 1 | 8000 | 7000 | 6000 | ... | null |
# | 2 | 9000 | null | null | ... | null |
# | 3 | null | 10000 | null | ... | null |
# +------+-------------+-------------+-------------+-----+-------------+
# Explanation: The revenue from Apr to Dec is null.
# Note that the result table has 13 columns (1 for the department id + 12 for the months).
#
# Write your MySQL query statement below
SELECT id,
SUM(CASE WHEN month = 'Jan' THEN revenue END) AS Jan_Revenue,
SUM(CASE WHEN month = 'Feb' THEN revenue END) AS Feb_Revenue,
SUM(CASE WHEN month = 'Mar' THEN revenue END) AS Mar_Revenue,
SUM(CASE WHEN month = 'Apr' THEN revenue END) AS Apr_Revenue,
SUM(CASE WHEN month = 'May' THEN revenue END) AS May_Revenue,
SUM(CASE WHEN month = 'Jun' THEN revenue END) AS Jun_Revenue,
SUM(CASE WHEN month = 'Jul' THEN revenue END) AS Jul_Revenue,
SUM(CASE WHEN month = 'Aug' THEN revenue END) AS Aug_Revenue,
SUM(CASE WHEN month = 'Sep' THEN revenue END) AS Sep_Revenue,
SUM(CASE WHEN month = 'Oct' THEN revenue END) AS Oct_Revenue,
SUM(CASE WHEN month = 'Nov' THEN revenue END) AS Nov_Revenue,
SUM(CASE WHEN month = 'Dec' THEN revenue END) AS Dec_Revenue
FROM Department
GROUP BY id;