#1321
Medium Database Restaurant growth
Database
58.2% acceptance
Feb 27, 2026
1149
380
Table: Customer
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| customer_id | int |
| name | varchar |
| visited_on | date |
| amount | int |
+---------------+---------+
In SQL,(customer_id, visited_on) is the primary key for this table.
This table contains data about customer transactions in a restaurant.
visited_on is the date on which the customer with ID (customer_id) has visited the restaurant.
amount is the total paid by a customer.
You are the restaurant owner and you want to analyze a possible expansion (there will be at least one customer every day).
Compute the moving average of how much the customer paid in a seven days window (i.e., current day + 6 days before). average_amount should be rounded to two decimal places.
Return the result table ordered by visited_on in ascending order.
The result format is in the following example.
Solution
SQL
#
# Table: Customer
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | customer_id | int |
# | name | varchar |
# | visited_on | date |
# | amount | int |
# +---------------+---------+
# In SQL,(customer_id, visited_on) is the primary key for this table.
# This table contains data about customer transactions in a restaurant.
# visited_on is the date on which the customer with ID (customer_id) has visited the restaurant.
# amount is the total paid by a customer.
# You are the restaurant owner and you want to analyze a possible expansion (there will be at least one customer every day).
# Compute the moving average of how much the customer paid in a seven days window (i.e., current day + 6 days before). average_amount should be rounded to two decimal places.
# Return the result table ordered by visited_on in ascending order.
# The result format is in the following example.
# Example 1:
# Input:
# Customer table:
# +-------------+--------------+--------------+-------------+
# | customer_id | name | visited_on | amount |
# +-------------+--------------+--------------+-------------+
# | 1 | Jhon | 2019-01-01 | 100 |
# | 2 | Daniel | 2019-01-02 | 110 |
# | 3 | Jade | 2019-01-03 | 120 |
# | 4 | Khaled | 2019-01-04 | 130 |
# | 5 | Winston | 2019-01-05 | 110 |
# | 6 | Elvis | 2019-01-06 | 140 |
# | 7 | Anna | 2019-01-07 | 150 |
# | 8 | Maria | 2019-01-08 | 80 |
# | 9 | Jaze | 2019-01-09 | 110 |
# | 1 | Jhon | 2019-01-10 | 130 |
# | 3 | Jade | 2019-01-10 | 150 |
# +-------------+--------------+--------------+-------------+
# Output:
# +--------------+--------------+----------------+
# | visited_on | amount | average_amount |
# +--------------+--------------+----------------+
# | 2019-01-07 | 860 | 122.86 |
# | 2019-01-08 | 840 | 120 |
# | 2019-01-09 | 840 | 120 |
# | 2019-01-10 | 1000 | 142.86 |
# +--------------+--------------+----------------+
# Explanation:
# 1st moving average from 2019-01-01 to 2019-01-07 has an average_amount of (100 + 110 + 120 + 130 + 110 + 140 + 150)/7 = 122.86
# 2nd moving average from 2019-01-02 to 2019-01-08 has an average_amount of (110 + 120 + 130 + 110 + 140 + 150 + 80)/7 = 120
# 3rd moving average from 2019-01-03 to 2019-01-09 has an average_amount of (120 + 130 + 110 + 140 + 150 + 80 + 110)/7 = 120
# 4th moving average from 2019-01-04 to 2019-01-10 has an average_amount of (130 + 110 + 140 + 150 + 80 + 110 + 130 + 150)/7 = 142.86
#
# Write your MySQL query statement below
SELECT visited_on,
SUM(amount) OVER (ORDER BY visited_on ROWS BETWEEN 6 PRECEDING AND CURRENT ROW) AS amount,
ROUND(AVG(amount) OVER (ORDER BY visited_on ROWS BETWEEN 6 PRECEDING AND CURRENT ROW), 2) AS average_amount
FROM (
SELECT visited_on, SUM(amount) AS amount
FROM Customer
GROUP BY visited_on
) daily
ORDER BY visited_on
LIMIT 18446744073709551615 OFFSET 6;