Generate a string with characters that have odd counts

String

78.5% acceptance

Feb 25, 2026

527

1287

Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times. The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.

Solution

Rust

Time O(1)

Space O(1)

LeetCode

solution.rs

impl Solution {
  pub fn generate_the_string(n: i32) -> String {
    if n % 2 == 1 {
      "a".repeat(n as usize)
    } else {
      "a".repeat(n as usize - 1) + "b"
    }
  }
}