#1412
Hard Database Find the quiet students in all exams
Database
58.1% acceptance
Mar 31, 2026
228
28
No description available.
Solution
Pandas
Time O(1)
Space O(1)
# Table: Student
#
# +---------------------+---------+
# | Column Name | Type |
# +---------------------+---------+
# | student_id | int |
# | student_name | varchar |
# +---------------------+---------+
# student_id is the primary key (column with unique values) for this table.
# student_name is the name of the student.
#
#
#
# Table: Exam
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | exam_id | int |
# | student_id | int |
# | score | int |
# +---------------+---------+
# (exam_id, student_id) is the primary key (combination of columns with unique values) for this table.
# Each row of this table indicates that the student with student_id had a score points in the exam with id exam_id.
#
#
#
# A quiet student is the one who took at least one exam and did not score the highest or the lowest score.
#
# Write a solution to report the students (student_id, student_name) being quiet in all exams. Do not return the student who has never taken any exam.
#
# Return the result table ordered by student_id.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Student table:
# +-------------+---------------+
# | student_id | student_name |
# +-------------+---------------+
# | 1 | Daniel |
# | 2 | Jade |
# | 3 | Stella |
# | 4 | Jonathan |
# | 5 | Will |
# +-------------+---------------+
# Exam table:
# +------------+--------------+-----------+
# | exam_id | student_id | score |
# +------------+--------------+-----------+
# | 10 | 1 | 70 |
# | 10 | 2 | 80 |
# | 10 | 3 | 90 |
# | 20 | 1 | 80 |
# | 30 | 1 | 70 |
# | 30 | 3 | 80 |
# | 30 | 4 | 90 |
# | 40 | 1 | 60 |
# | 40 | 2 | 70 |
# | 40 | 4 | 80 |
# +------------+--------------+-----------+
# Output:
# +-------------+---------------+
# | student_id | student_name |
# +-------------+---------------+
# | 2 | Jade |
# +-------------+---------------+
# Explanation:
# For exam 1: Student 1 and 3 hold the lowest and high scores respectively.
# For exam 2: Student 1 hold both highest and lowest score.
# For exam 3 and 4: Student 1 and 4 hold the lowest and high scores respectively.
# Student 2 and 5 have never got the highest or lowest in any of the exams.
# Since student 5 is not taking any exam, he is excluded from the result.
# So, we only return the information of Student 2.
import pandas as pd
def find_quiet_students(student: pd.DataFrame, exam: pd.DataFrame) -> pd.DataFrame:
if exam.empty:
return pd.DataFrame(columns=['student_id', 'student_name'])
exam = exam.merge(
exam.groupby('exam_id')['score'].agg(['min', 'max']),
on='exam_id'
)
loud = exam[(exam['score'] == exam['min']) | (exam['score'] == exam['max'])]['student_id'].unique()
took_exam = exam['student_id'].unique()
quiet_ids = set(took_exam) - set(loud)
result = student[student['student_id'].isin(quiet_ids)][['student_id', 'student_name']]
return result.sort_values('student_id')