#1549
Medium Database The most recent orders for each product
Database
65.0% acceptance
Mar 31, 2026
141
12
No description available.
Solution
Pandas
Time O(1)
Space O(1)
# Table: Customers
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | customer_id | int |
# | name | varchar |
# +---------------+---------+
# customer_id is the column with unique values for this table.
# This table contains information about the customers.
#
#
#
# Table: Orders
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | order_id | int |
# | order_date | date |
# | customer_id | int |
# | product_id | int |
# +---------------+---------+
# order_id is the column with unique values for this table.
# This table contains information about the orders made by customer_id.
# There will be no product ordered by the same user more than once in one day.
#
#
#
# Table: Products
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | product_id | int |
# | product_name | varchar |
# | price | int |
# +---------------+---------+
# product_id is the column with unique values for this table.
# This table contains information about the Products.
#
#
#
# Write a solution to find the most recent order(s) of each product.
#
# Return the result table ordered by product_name in ascending order and in case of a tie by the product_id in ascending order. If there still a tie, order them by order_id in ascending order.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Customers table:
# +-------------+-----------+
# | customer_id | name |
# +-------------+-----------+
# | 1 | Winston |
# | 2 | Jonathan |
# | 3 | Annabelle |
# | 4 | Marwan |
# | 5 | Khaled |
# +-------------+-----------+
# Orders table:
# +----------+------------+-------------+------------+
# | order_id | order_date | customer_id | product_id |
# +----------+------------+-------------+------------+
# | 1 | 2020-07-31 | 1 | 1 |
# | 2 | 2020-07-30 | 2 | 2 |
# | 3 | 2020-08-29 | 3 | 3 |
# | 4 | 2020-07-29 | 4 | 1 |
# | 5 | 2020-06-10 | 1 | 2 |
# | 6 | 2020-08-01 | 2 | 1 |
# | 7 | 2020-08-01 | 3 | 1 |
# | 8 | 2020-08-03 | 1 | 2 |
# | 9 | 2020-08-07 | 2 | 3 |
# | 10 | 2020-07-15 | 1 | 2 |
# +----------+------------+-------------+------------+
# Products table:
# +------------+--------------+-------+
# | product_id | product_name | price |
# +------------+--------------+-------+
# | 1 | keyboard | 120 |
# | 2 | mouse | 80 |
# | 3 | screen | 600 |
# | 4 | hard disk | 450 |
# +------------+--------------+-------+
# Output:
# +--------------+------------+----------+------------+
# | product_name | product_id | order_id | order_date |
# +--------------+------------+----------+------------+
# | keyboard | 1 | 6 | 2020-08-01 |
# | keyboard | 1 | 7 | 2020-08-01 |
# | mouse | 2 | 8 | 2020-08-03 |
# | screen | 3 | 3 | 2020-08-29 |
# +--------------+------------+----------+------------+
# Explanation:
# keyboard's most recent order is in 2020-08-01, it was ordered two times this day.
# mouse's most recent order is in 2020-08-03, it was ordered only once this day.
# screen's most recent order is in 2020-08-29, it was ordered only once this day.
# The hard disk was never ordered and we do not include it in the result table.
import pandas as pd
def most_recent_orders(customers: pd.DataFrame, orders: pd.DataFrame, products: pd.DataFrame) -> pd.DataFrame:
merged = orders.merge(products, on='product_id')
merged['max_date'] = merged.groupby('product_id')['order_date'].transform('max')
result = merged[merged['order_date'] == merged['max_date']]
result = result[['product_name', 'product_id', 'order_id', 'order_date']]
result = result.sort_values(['product_name', 'product_id', 'order_id'])
return result