#1596
Medium Database The most frequently ordered products for each customer
Database
77.7% acceptance
Mar 31, 2026
262
17
No description available.
Solution
Pandas
Time O(1)
Space O(1)
# Table: Customers
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | customer_id | int |
# | name | varchar |
# +---------------+---------+
# customer_id is the column with unique values for this table.
# This table contains information about the customers.
#
#
#
# Table: Orders
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | order_id | int |
# | order_date | date |
# | customer_id | int |
# | product_id | int |
# +---------------+---------+
# order_id is the column with unique values for this table.
# This table contains information about the orders made by customer_id.
# No customer will order the same product more than once in a single day.
#
#
#
# Table: Products
#
# +---------------+---------+
# | Column Name | Type |
# +---------------+---------+
# | product_id | int |
# | product_name | varchar |
# | price | int |
# +---------------+---------+
# product_id is the column with unique values for this table.
# This table contains information about the products.
#
#
#
# Write a solution to find the most frequently ordered product(s) for each customer.
#
# The result table should have the product_id and product_name for each customer_id who ordered at least one order.
#
# Return the result table in any order.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Customers table:
# +-------------+-------+
# | customer_id | name |
# +-------------+-------+
# | 1 | Alice |
# | 2 | Bob |
# | 3 | Tom |
# | 4 | Jerry |
# | 5 | John |
# +-------------+-------+
# Orders table:
# +----------+------------+-------------+------------+
# | order_id | order_date | customer_id | product_id |
# +----------+------------+-------------+------------+
# | 1 | 2020-07-31 | 1 | 1 |
# | 2 | 2020-07-30 | 2 | 2 |
# | 3 | 2020-08-29 | 3 | 3 |
# | 4 | 2020-07-29 | 4 | 1 |
# | 5 | 2020-06-10 | 1 | 2 |
# | 6 | 2020-08-01 | 2 | 1 |
# | 7 | 2020-08-01 | 3 | 3 |
# | 8 | 2020-08-03 | 1 | 2 |
# | 9 | 2020-08-07 | 2 | 3 |
# | 10 | 2020-07-15 | 1 | 2 |
# +----------+------------+-------------+------------+
# Products table:
# +------------+--------------+-------+
# | product_id | product_name | price |
# +------------+--------------+-------+
# | 1 | keyboard | 120 |
# | 2 | mouse | 80 |
# | 3 | screen | 600 |
# | 4 | hard disk | 450 |
# +------------+--------------+-------+
# Output:
# +-------------+------------+--------------+
# | customer_id | product_id | product_name |
# +-------------+------------+--------------+
# | 1 | 2 | mouse |
# | 2 | 1 | keyboard |
# | 2 | 2 | mouse |
# | 2 | 3 | screen |
# | 3 | 3 | screen |
# | 4 | 1 | keyboard |
# +-------------+------------+--------------+
# Explanation:
# Alice (customer 1) ordered the mouse three times and the keyboard one time, so the mouse is the most frequently ordered product for them.
# Bob (customer 2) ordered the keyboard, the mouse, and the screen one time, so those are the most frequently ordered products for them.
# Tom (customer 3) only ordered the screen (two times), so that is the most frequently ordered product for them.
# Jerry (customer 4) only ordered the keyboard (one time), so that is the most frequently ordered product for them.
# John (customer 5) did not order anything, so we do not include them in the result table.
import pandas as pd
def most_frequently_products(customers: pd.DataFrame, orders: pd.DataFrame, products: pd.DataFrame) -> pd.DataFrame:
counts = orders.groupby(['customer_id', 'product_id']).size().reset_index(name='cnt')
counts['max_cnt'] = counts.groupby('customer_id')['cnt'].transform('max')
top = counts[counts['cnt'] == counts['max_cnt']]
result = top.merge(products, on='product_id')
result = result[['customer_id', 'product_id', 'product_name']]
return result