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#1596
Medium Database

The most frequently ordered products for each customer

Database
77.7% acceptance
Mar 31, 2026
262
17

No description available.

Solution

Pandas
Time O(1)
Space O(1)
LeetCode
solution.pandas
# Table: Customers
# 
# +---------------+---------+
# | Column Name   | Type    |
# +---------------+---------+
# | customer_id   | int     |
# | name          | varchar |
# +---------------+---------+
# customer_id is the column with unique values for this table.
# This table contains information about the customers.
# 
#  
# 
# Table: Orders
# 
# +---------------+---------+
# | Column Name   | Type    |
# +---------------+---------+
# | order_id      | int     |
# | order_date    | date    |
# | customer_id   | int     |
# | product_id    | int     |
# +---------------+---------+
# order_id is the column with unique values for this table.
# This table contains information about the orders made by customer_id.
# No customer will order the same product more than once in a single day.
# 
#  
# 
# Table: Products
# 
# +---------------+---------+
# | Column Name   | Type    |
# +---------------+---------+
# | product_id    | int     |
# | product_name  | varchar |
# | price         | int     |
# +---------------+---------+
# product_id is the column with unique values for this table.
# This table contains information about the products.
# 
#  
# 
# Write a solution to find the most frequently ordered product(s) for each customer.
# 
# The result table should have the product_id and product_name for each customer_id who ordered at least one order.
# 
# Return the result table in any order.
# 
# The result format is in the following example.
#
# Example 1:
# Input:
# Customers table:
# +-------------+-------+
# | customer_id | name  |
# +-------------+-------+
# | 1           | Alice |
# | 2           | Bob   |
# | 3           | Tom   |
# | 4           | Jerry |
# | 5           | John  |
# +-------------+-------+
# Orders table:
# +----------+------------+-------------+------------+
# | order_id | order_date | customer_id | product_id |
# +----------+------------+-------------+------------+
# | 1        | 2020-07-31 | 1           | 1          |
# | 2        | 2020-07-30 | 2           | 2          |
# | 3        | 2020-08-29 | 3           | 3          |
# | 4        | 2020-07-29 | 4           | 1          |
# | 5        | 2020-06-10 | 1           | 2          |
# | 6        | 2020-08-01 | 2           | 1          |
# | 7        | 2020-08-01 | 3           | 3          |
# | 8        | 2020-08-03 | 1           | 2          |
# | 9        | 2020-08-07 | 2           | 3          |
# | 10       | 2020-07-15 | 1           | 2          |
# +----------+------------+-------------+------------+
# Products table:
# +------------+--------------+-------+
# | product_id | product_name | price |
# +------------+--------------+-------+
# | 1          | keyboard     | 120   |
# | 2          | mouse        | 80    |
# | 3          | screen       | 600   |
# | 4          | hard disk    | 450   |
# +------------+--------------+-------+
# Output:
# +-------------+------------+--------------+
# | customer_id | product_id | product_name |
# +-------------+------------+--------------+
# | 1           | 2          | mouse        |
# | 2           | 1          | keyboard     |
# | 2           | 2          | mouse        |
# | 2           | 3          | screen       |
# | 3           | 3          | screen       |
# | 4           | 1          | keyboard     |
# +-------------+------------+--------------+
# Explanation:
# Alice (customer 1) ordered the mouse three times and the keyboard one time, so the mouse is the most frequently ordered product for them.
# Bob (customer 2) ordered the keyboard, the mouse, and the screen one time, so those are the most frequently ordered products for them.
# Tom (customer 3) only ordered the screen (two times), so that is the most frequently ordered product for them.
# Jerry (customer 4) only ordered the keyboard (one time), so that is the most frequently ordered product for them.
# John (customer 5) did not order anything, so we do not include them in the result table.

import pandas as pd

def most_frequently_products(customers: pd.DataFrame, orders: pd.DataFrame, products: pd.DataFrame) -> pd.DataFrame:
  counts = orders.groupby(['customer_id', 'product_id']).size().reset_index(name='cnt')
  counts['max_cnt'] = counts.groupby('customer_id')['cnt'].transform('max')
  top = counts[counts['cnt'] == counts['max_cnt']]
  result = top.merge(products, on='product_id')
  result = result[['customer_id', 'product_id', 'product_name']]
  return result