#1634
Medium Algorithms Add two polynomials represented as linked lists
Linked List Math Two Pointers
61.0% acceptance
Mar 31, 2026
173
14
A polynomial linked list is a special type of linked list where every node represents a term in a polynomial expression.
Each node has three attributes:
coefficient: an integer representing the number multiplier of the term. The coefficient of the term 9x4 is 9.
power: an integer representing the exponent. The power of the term 9x4 is 4.
next: a pointer to the next node in the list, or null if it is the last node of the list.
For example, the polynomial 5x3 + 4x - 7 is represented by the polynomial linked list illustrated below:
The polynomial linked list must be in its standard form: the polynomial must be in strictly descending order by its power value. Also, terms with a coefficient of 0 are omitted.
Given two polynomial linked list heads, poly1 and poly2, add the polynomials together and return the head of the sum of the polynomials.
PolyNode format:
The input/output format is as a list of n nodes, where each node is represented as its [coefficient, power]. For example, the polynomial 5x3 + 4x - 7 would be represented as: [[5,3],[4,1],[-7,0]].
Solution
C++
Time O(n)
Space O(1)
/**
* Definition for polynomial singly-linked list.
* struct PolyNode {
* int coefficient, power;
* PolyNode *next;
* PolyNode(): coefficient(0), power(0), next(nullptr) {};
* PolyNode(int x, int y): coefficient(x), power(y), next(nullptr) {};
* PolyNode(int x, int y, PolyNode* next): coefficient(x), power(y), next(next) {};
* };
*/
class Solution {
public:
PolyNode* addPoly(PolyNode* poly1, PolyNode* poly2) {
PolyNode dummy;
PolyNode* curr = &dummy;
while (poly1 && poly2) {
if (poly1->power > poly2->power) {
curr->next = poly1;
poly1 = poly1->next;
} else if (poly1->power < poly2->power) {
curr->next = poly2;
poly2 = poly2->next;
} else {
int coeff = poly1->coefficient + poly2->coefficient;
if (coeff != 0) {
curr->next = new PolyNode(coeff, poly1->power);
curr = curr->next;
}
poly1 = poly1->next;
poly2 = poly2->next;
continue;
}
curr = curr->next;
}
curr->next = poly1 ? poly1 : poly2;
return dummy.next;
}
};