Calculate special bonus

#
# Table: Employees
# +-------------+---------+
# | Column Name | Type    |
# +-------------+---------+
# | employee_id | int     |
# | name        | varchar |
# | salary      | int     |
# +-------------+---------+
# employee_id is the primary key (column with unique values) for this table.
# Each row of this table indicates the employee ID, employee name, and salary.
# Write a solution to calculate the bonus of each employee. The bonus of an employee is 100% of their salary if the ID of the employee is an odd number and the employee's name does not start with the character 'M'. The bonus of an employee is 0 otherwise.
# Return the result table ordered by employee_id.
# The result format is in the following example.
# Example 1:
# Input:
# Employees table:
# +-------------+---------+--------+
# | employee_id | name    | salary |
# +-------------+---------+--------+
# | 2           | Meir    | 3000   |
# | 3           | Michael | 3800   |
# | 7           | Addilyn | 7400   |
# | 8           | Juan    | 6100   |
# | 9           | Kannon  | 7700   |
# +-------------+---------+--------+
# Output:
# +-------------+-------+
# | employee_id | bonus |
# +-------------+-------+
# | 2           | 0     |
# | 3           | 0     |
# | 7           | 7400  |
# | 8           | 0     |
# | 9           | 7700  |
# +-------------+-------+
# Explanation:
# The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id.
# The employee with ID 3 gets 0 bonus because their name starts with 'M'.
# The rest of the employees get a 100% bonus.
#

# Write your MySQL query statement below

SELECT employee_id,
  CASE WHEN employee_id % 2 = 1 AND name NOT LIKE 'M%' THEN salary ELSE 0 END AS bonus
FROM Employees
ORDER BY employee_id;