#197
Easy Database Rising temperature
Database
51.0% acceptance
Feb 27, 2026
4182
741
Table: Weather
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| recordDate | date |
| temperature | int |
+---------------+---------+
id is the column with unique values for this table.
There are no different rows with the same recordDate.
This table contains information about the temperature on a certain day.
Write a solution to find all dates' id with higher temperatures compared to its previous dates (yesterday).
Return the result table in any order.
The result format is in the following example.
Solution
SQL
--
-- Table: Weather
-- +---------------+---------+
-- | Column Name | Type |
-- +---------------+---------+
-- | id | int |
-- | recordDate | date |
-- | temperature | int |
-- +---------------+---------+
-- id is the column with unique values for this table.
-- There are no different rows with the same recordDate.
-- This table contains information about the temperature on a certain day.
-- Write a solution to find all dates' id with higher temperatures compared to its previous dates (yesterday).
-- Return the result table in any order.
-- The result format is in the following example.
-- Example 1:
-- Input:
-- Weather table:
-- +----+------------+-------------+
-- | id | recordDate | temperature |
-- +----+------------+-------------+
-- | 1 | 2015-01-01 | 10 |
-- | 2 | 2015-01-02 | 25 |
-- | 3 | 2015-01-03 | 20 |
-- | 4 | 2015-01-04 | 30 |
-- +----+------------+-------------+
-- Output:
-- +----+
-- | id |
-- +----+
-- | 2 |
-- | 4 |
-- +----+
-- Explanation:
-- In 2015-01-02, the temperature was higher than the previous day (10 -> 25).
-- In 2015-01-04, the temperature was higher than the previous day (20 -> 30).
--
# Write your MySQL query statement below
SELECT w1.id
FROM Weather w1
JOIN Weather w2 ON w1.recordDate = DATE_ADD(w2.recordDate, INTERVAL 1 DAY)
WHERE w1.temperature > w2.temperature;