#2176
Easy Algorithms Count equal and divisible pairs in an array
Array
84.0% acceptance
Feb 25, 2026
1038
69
Given a 0-indexed integer array nums and an integer k, return the number of pairs (i, j)
where 0 <= i < j < n, such that nums[i] == nums[j] and (i * j) is divisible by k.
Solution
Rust
Time O(n²)
Space O(1)
impl Solution {
pub fn count_pairs(nums: Vec<i32>, k: i32) -> i32 {
let n = nums.len();
let mut count = 0;
for i in 0..n {
for j in i + 1..n {
if nums[i] == nums[j] && (i * j) as i32 % k == 0 {
count += 1;
}
}
}
count
}
}