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#2308
Medium Database

Arrange table by gender

Database
70.8% acceptance
Mar 31, 2026
90
15

No description available.

Solution

Pandas
Time O(n)
Space O(1)
LeetCode
solution.pandas
# Table: Genders
# 
# +-------------+---------+
# | Column Name | Type    |
# +-------------+---------+
# | user_id     | int     |
# | gender      | varchar |
# +-------------+---------+
# user_id is the primary key (column with unique values) for this table.
# gender is ENUM (category) of type 'female', 'male', or 'other'.
# Each row in this table contains the ID of a user and their gender.
# The table has an equal number of 'female', 'male', and 'other'.
# 
#  
# 
# Write a solution to rearrange the Genders table such that the rows alternate between 'female', 'other', and 'male' in order. The table should be rearranged such that the IDs of each gender are sorted in ascending order.
# 
# Return the result table in the mentioned order.
# 
# The result format is shown in the following example.
#
# Example 1:
# Input:
# Genders table:
# +---------+--------+
# | user_id | gender |
# +---------+--------+
# | 4       | male   |
# | 7       | female |
# | 2       | other  |
# | 5       | male   |
# | 3       | female |
# | 8       | male   |
# | 6       | other  |
# | 1       | other  |
# | 9       | female |
# +---------+--------+
# Output:
# +---------+--------+
# | user_id | gender |
# +---------+--------+
# | 3       | female |
# | 1       | other  |
# | 4       | male   |
# | 7       | female |
# | 2       | other  |
# | 5       | male   |
# | 9       | female |
# | 6       | other  |
# | 8       | male   |
# +---------+--------+
# Explanation:
# Female gender: IDs 3, 7, and 9.
# Other gender: IDs 1, 2, and 6.
# Male gender: IDs 4, 5, and 8.
# We arrange the table alternating between 'female', 'other', and 'male'.
# Note that the IDs of each gender are sorted in ascending order.

import pandas as pd

def arrange_table(genders: pd.DataFrame) -> pd.DataFrame:
  genders['rn'] = genders.groupby('gender')['user_id'].rank(method='first')
  order = {'female': 0, 'other': 1, 'male': 2}
  genders['gender_order'] = genders['gender'].map(order)
  genders = genders.sort_values(['rn', 'gender_order'])
  return genders[['user_id', 'gender']]