#2474
Hard Database Customers with strictly increasing purchases
Database
50.1% acceptance
Mar 31, 2026
46
6
No description available.
Solution
Pandas
Time O(n)
Space O(1)
# Table: Orders
#
# +--------------+------+
# | Column Name | Type |
# +--------------+------+
# | order_id | int |
# | customer_id | int |
# | order_date | date |
# | price | int |
# +--------------+------+
# order_id is the column with unique values for this table.
# Each row contains the id of an order, the id of customer that ordered it, the date of the order, and its price.
#
#
#
# Write a solution to report the IDs of the customers with the total purchases strictly increasing yearly.
#
# The total purchases of a customer in one year is the sum of the prices of their orders in that year. If for some year the customer did not make any order, we consider the total purchases 0.
#
# The first year to consider for each customer is the year of their first order.
#
# The last year to consider for each customer is the year of their last order.
#
# Return the result table in any order.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Orders table:
# +----------+-------------+------------+-------+
# | order_id | customer_id | order_date | price |
# +----------+-------------+------------+-------+
# | 1 | 1 | 2019-07-01 | 1100 |
# | 2 | 1 | 2019-11-01 | 1200 |
# | 3 | 1 | 2020-05-26 | 3000 |
# | 4 | 1 | 2021-08-31 | 3100 |
# | 5 | 1 | 2022-12-07 | 4700 |
# | 6 | 2 | 2015-01-01 | 700 |
# | 7 | 2 | 2017-11-07 | 1000 |
# | 8 | 3 | 2017-01-01 | 900 |
# | 9 | 3 | 2018-11-07 | 900 |
# +----------+-------------+------------+-------+
# Output:
# +-------------+
# | customer_id |
# +-------------+
# | 1 |
# +-------------+
# Explanation:
# Customer 1: The first year is 2019 and the last year is 2022
# - 2019: 1100 + 1200 = 2300
# - 2020: 3000
# - 2021: 3100
# - 2022: 4700
# We can see that the total purchases are strictly increasing yearly, so we include customer 1 in the answer.
#
# Customer 2: The first year is 2015 and the last year is 2017
# - 2015: 700
# - 2016: 0
# - 2017: 1000
# We do not include customer 2 in the answer because the total purchases are not strictly increasing. Note that customer 2 did not make any purchases in 2016.
#
# Customer 3: The first year is 2017, and the last year is 2018
# - 2017: 900
# - 2018: 900
# We do not include customer 3 in the answer because the total purchases are not strictly increasing.
import pandas as pd
def find_specific_customers(orders: pd.DataFrame) -> pd.DataFrame:
orders['year'] = pd.to_datetime(orders['order_date']).dt.year
yearly = orders.groupby(['customer_id', 'year'])['price'].sum().reset_index()
def is_strictly_increasing(group):
group = group.sort_values('year')
min_year, max_year = group['year'].min(), group['year'].max()
all_years = pd.DataFrame({'year': range(min_year, max_year + 1)})
full = all_years.merge(group[['year', 'price']], on='year', how='left').fillna(0)
return (full['price'].diff().dropna() > 0).all()
result = yearly.groupby('customer_id').filter(is_strictly_increasing)
return pd.DataFrame({'customer_id': result['customer_id'].unique()})