#26
Easy Algorithms Remove duplicates from sorted array
Array Two Pointers
62.3% acceptance
Jan 12, 2026
18819
20480
Given an integer array nums sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same.
Consider the number of unique elements in nums to be k. After removing duplicates, return the number of unique elements k.
The first k elements of nums should contain the unique numbers in sorted order. The remaining elements beyond index k - 1 can be ignored.
Custom Judge:
The judge will test your solution with the following code:
int[] nums = [...]; // Input array
int[] expectedNums = [...]; // The expected answer with correct length
int k = removeDuplicates(nums); // Calls your implementation
assert k == expectedNums.length;
for (int i = 0; i < k; i++) {
assert nums[i] == expectedNums[i];
}
If all assertions pass, then your solution will be accepted.
Solution
Rust
Time O(n)
Space O(1)
impl Solution {
pub fn remove_duplicates(nums: &mut Vec<i32>) -> i32 {
if nums.is_empty() {
return 0;
}
let mut write_index = 1;
for read_index in 1..nums.len() {
if nums[read_index] != nums[write_index - 1] {
nums[write_index] = nums[read_index];
write_index += 1;
}
}
write_index as i32
}
}