Promise time limit

83.2% acceptance

Mar 2, 2026

574

Given an asynchronous function fn and a time t in milliseconds, return a new time limited version of the input function. fn takes arguments provided to the time limited function. The time limited function should follow these rules: If the fn completes within the time limit of t milliseconds, the time limited function should resolve with the result. If the execution of the fn exceeds the time limit, the time limited function should reject with the string "Time Limit Exceeded".

Solution

TypeScript

Time O(1)

Space O(1)

LeetCode

solution.ts

type Fn = (...params: any[]) => Promise<any>;

function timeLimit(fn: Fn, t: number): Fn {
  return async function (...args: any[]): Promise<any> {
  const timeout = new Promise<never>((_, reject) =>
    setTimeout(() => reject("Time Limit Exceeded"), t),
  );
  return Promise.race([fn(...args), timeout]);
  };
}

/**
 * const limited = timeLimit((t) => new Promise(res => setTimeout(res, t)), 100);
 * limited(150).catch(console.log) // "Time Limit Exceeded" at t=100ms
 */