#3126
Medium Database Server utilization time
Database
60.6% acceptance
Mar 31, 2026
10
16
No description available.
Solution
Pandas
Time O(n)
Space O(1)
# Table: Servers
#
# +----------------+----------+
# | Column Name | Type |
# +----------------+----------+
# | server_id | int |
# | status_time | datetime |
# | session_status | enum |
# +----------------+----------+
# (server_id, status_time, session_status) is the primary key (combination of columns with unique values) for this table.
# session_status is an ENUM (category) type of ('start', 'stop').
# Each row of this table contains server_id, status_time, and session_status.
#
# Write a solution to find the total time when servers were running. The output should be rounded down to the nearest number of full days.
#
# Return the result table in any order.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Servers table:
# +-----------+---------------------+----------------+
# | server_id | status_time | session_status |
# +-----------+---------------------+----------------+
# | 3 | 2023-11-04 16:29:47 | start |
# | 3 | 2023-11-05 01:49:47 | stop |
# | 3 | 2023-11-25 01:37:08 | start |
# | 3 | 2023-11-25 03:50:08 | stop |
# | 1 | 2023-11-13 03:05:31 | start |
# | 1 | 2023-11-13 11:10:31 | stop |
# | 4 | 2023-11-29 15:11:17 | start |
# | 4 | 2023-11-29 15:42:17 | stop |
# | 4 | 2023-11-20 00:31:44 | start |
# | 4 | 2023-11-20 07:03:44 | stop |
# | 1 | 2023-11-20 00:27:11 | start |
# | 1 | 2023-11-20 01:41:11 | stop |
# | 3 | 2023-11-04 23:16:48 | start |
# | 3 | 2023-11-05 01:15:48 | stop |
# | 4 | 2023-11-30 15:09:18 | start |
# | 4 | 2023-11-30 20:48:18 | stop |
# | 4 | 2023-11-25 21:09:06 | start |
# | 4 | 2023-11-26 04:58:06 | stop |
# | 5 | 2023-11-16 19:42:22 | start |
# | 5 | 2023-11-16 21:08:22 | stop |
# +-----------+---------------------+----------------+
# Output:
# +-------------------+
# | total_uptime_days |
# +-------------------+
# | 1 |
# +-------------------+
# Explanation:
# For server ID 3:
# From 2023-11-04 16:29:47 to 2023-11-05 01:49:47: ~9.3 hours
# From 2023-11-25 01:37:08 to 2023-11-25 03:50:08: ~2.2 hours
# From 2023-11-04 23:16:48 to 2023-11-05 01:15:48: ~1.98 hours
# Total for server 3: ~13.48 hours
# For server ID 1:
# From 2023-11-13 03:05:31 to 2023-11-13 11:10:31: ~8 hours
# From 2023-11-20 00:27:11 to 2023-11-20 01:41:11: ~1.23 hours
# Total for server 1: ~9.23 hours
# For server ID 4:
# From 2023-11-29 15:11:17 to 2023-11-29 15:42:17: ~0.52 hours
# From 2023-11-20 00:31:44 to 2023-11-20 07:03:44: ~6.53 hours
# From 2023-11-30 15:09:18 to 2023-11-30 20:48:18: ~5.65 hours
# From 2023-11-25 21:09:06 to 2023-11-26 04:58:06: ~7.82 hours
# Total for server 4: ~20.52 hours
# For server ID 5:
# From 2023-11-16 19:42:22 to 2023-11-16 21:08:22: ~1.43 hours
# Total for server 5: ~1.43 hours
# The accumulated runtime for all servers totals approximately 44.46 hours, equivalent to one full day plus some additional hours. However, since we consider only full days, the final output is rounded to 1 full day.
import pandas as pd
def server_utilization_time(servers: pd.DataFrame) -> pd.DataFrame:
servers['status_time'] = pd.to_datetime(servers['status_time'])
starts = servers[servers['session_status'] == 'start'].sort_values(['server_id', 'status_time'])
stops = servers[servers['session_status'] == 'stop'].sort_values(['server_id', 'status_time'])
merged = starts.merge(stops, on='server_id', suffixes=('_start', '_stop'))
# Match each start with the earliest stop after it
merged = merged[merged['status_time_stop'] > merged['status_time_start']]
merged['duration'] = (merged['status_time_stop'] - merged['status_time_start']).dt.total_seconds()
# For each start, take the closest stop
merged = merged.sort_values('duration').drop_duplicates(subset=['server_id', 'status_time_start'], keep='first')
total_seconds = merged['duration'].sum()
total_days = int(total_seconds // 86400)
return pd.DataFrame({'total_uptime_days': [total_days]})