Find valid emails

#
# Table: Users
# +-----------------+---------+
# | Column Name     | Type    |
# +-----------------+---------+
# | user_id         | int     |
# | email           | varchar |
# +-----------------+---------+
# (user_id) is the unique key for this table.
# Each row contains a user's unique ID and email address.
# Write a solution to find all the valid email addresses. A valid email address meets the following criteria:
# It contains exactly one @ symbol.
# It ends with .com.
# The part before the @ symbol contains only alphanumeric characters and underscores.
# The part after the @ symbol and before .com contains a domain name that contains only letters.
# Return the result table ordered by user_id in ascending order.
# Example:
# Input:
# Users table:
# +---------+---------------------+
# | user_id | email               |
# +---------+---------------------+
# | 1       | alice@example.com   |
# | 2       | bob_at_example.com  |
# | 3       | charlie@example.net |
# | 4       | david@domain.com    |
# | 5       | eve@invalid         |
# +---------+---------------------+
# Output:
# +---------+-------------------+
# | user_id | email             |
# +---------+-------------------+
# | 1       | alice@example.com |
# | 4       | david@domain.com  |
# +---------+-------------------+
# Explanation:
# alice@example.com is valid because it contains one @, alice is alphanumeric, and example.com starts with a letter and ends with .com.
# bob_at_example.com is invalid because it contains an underscore instead of an @.
# charlie@example.net is invalid because the domain does not end with .com.
# david@domain.com is valid because it meets all criteria.
# eve@invalid is invalid because the domain does not end with .com.
# Result table is ordered by user_id in ascending order.
#

# Write your MySQL query statement below

SELECT user_id, email
FROM Users
WHERE email REGEXP '^[a-zA-Z0-9_]+@[a-zA-Z]+\\.com$'
ORDER BY user_id;