#3497
Medium Database Analyze subscription conversion
Database
74.1% acceptance
Feb 27, 2026
61
6
Table: UserActivity
+------------------+---------+
| Column Name | Type |
+------------------+---------+
| user_id | int |
| activity_date | date |
| activity_type | varchar |
| activity_duration| int |
+------------------+---------+
(user_id, activity_date, activity_type) is the unique key for this table.
activity_type is one of ('free_trial', 'paid', 'cancelled').
activity_duration is the number of minutes the user spent on the platform that day.
Each row represents a user's activity on a specific date.
A subscription service wants to analyze user behavior patterns. The company offers a 7-day free trial, after which users can subscribe to a paid plan or cancel. Write a solution to:
Find users who converted from free trial to paid subscription
Calculate each user's average daily activity duration during their free trial period (rounded to 2 decimal places)
Calculate each user's average daily activity duration during their paid subscription period (rounded to 2 decimal places)
Return the result table ordered by user_id in ascending order.
The result format is in the following example.
Solution
SQL
#
# Table: UserActivity
# +------------------+---------+
# | Column Name | Type |
# +------------------+---------+
# | user_id | int |
# | activity_date | date |
# | activity_type | varchar |
# | activity_duration| int |
# +------------------+---------+
# (user_id, activity_date, activity_type) is the unique key for this table.
# activity_type is one of ('free_trial', 'paid', 'cancelled').
# activity_duration is the number of minutes the user spent on the platform that day.
# Each row represents a user's activity on a specific date.
# A subscription service wants to analyze user behavior patterns. The company offers a 7-day free trial, after which users can subscribe to a paid plan or cancel. Write a solution to:
# Find users who converted from free trial to paid subscription
# Calculate each user's average daily activity duration during their free trial period (rounded to 2 decimal places)
# Calculate each user's average daily activity duration during their paid subscription period (rounded to 2 decimal places)
# Return the result table ordered by user_id in ascending order.
# The result format is in the following example.
# Example:
# Input:
# UserActivity table:
# +---------+---------------+---------------+-------------------+
# | user_id | activity_date | activity_type | activity_duration |
# +---------+---------------+---------------+-------------------+
# | 1 | 2023-01-01 | free_trial | 45 |
# | 1 | 2023-01-02 | free_trial | 30 |
# | 1 | 2023-01-05 | free_trial | 60 |
# | 1 | 2023-01-10 | paid | 75 |
# | 1 | 2023-01-12 | paid | 90 |
# | 1 | 2023-01-15 | paid | 65 |
# | 2 | 2023-02-01 | free_trial | 55 |
# | 2 | 2023-02-03 | free_trial | 25 |
# | 2 | 2023-02-07 | free_trial | 50 |
# | 2 | 2023-02-10 | cancelled | 0 |
# | 3 | 2023-03-05 | free_trial | 70 |
# | 3 | 2023-03-06 | free_trial | 60 |
# | 3 | 2023-03-08 | free_trial | 80 |
# | 3 | 2023-03-12 | paid | 50 |
# | 3 | 2023-03-15 | paid | 55 |
# | 3 | 2023-03-20 | paid | 85 |
# | 4 | 2023-04-01 | free_trial | 40 |
# | 4 | 2023-04-03 | free_trial | 35 |
# | 4 | 2023-04-05 | paid | 45 |
# | 4 | 2023-04-07 | cancelled | 0 |
# +---------+---------------+---------------+-------------------+
# Output:
# +---------+--------------------+-------------------+
# | user_id | trial_avg_duration | paid_avg_duration |
# +---------+--------------------+-------------------+
# | 1 | 45.00 | 76.67 |
# | 3 | 70.00 | 63.33 |
# | 4 | 37.50 | 45.00 |
# +---------+--------------------+-------------------+
# Explanation:
# User 1:
# Had 3 days of free trial with durations of 45, 30, and 60 minutes.
# Average trial duration: (45 + 30 + 60) / 3 = 45.00 minutes.
# Had 3 days of paid subscription with durations of 75, 90, and 65 minutes.
# Average paid duration: (75 + 90 + 65) / 3 = 76.67 minutes.
# User 2:
# Had 3 days of free trial with durations of 55, 25, and 50 minutes.
# Average trial duration: (55 + 25 + 50) / 3 = 43.33 minutes.
# Did not convert to a paid subscription (only had free_trial and cancelled activities).
# Not included in the output because they didn't convert to paid.
# User 3:
# Had 3 days of free trial with durations of 70, 60, and 80 minutes.
# Average trial duration: (70 + 60 + 80) / 3 = 70.00 minutes.
# Had 3 days of paid subscription with durations of 50, 55, and 85 minutes.
# Average paid duration: (50 + 55 + 85) / 3 = 63.33 minutes.
# User 4:
# Had 2 days of free trial with durations of 40 and 35 minutes.
# Average trial duration: (40 + 35) / 2 = 37.50 minutes.
# Had 1 day of paid subscription with duration of 45 minutes before cancelling.
# Average paid duration: 45.00 minutes.
# The result table only includes users who converted from free trial to paid subscription (users 1, 3, and 4), and is ordered by user_id in ascending order.
#
# Write your MySQL query statement below
SELECT user_id,
ROUND(AVG(CASE WHEN activity_type = 'free_trial' THEN activity_duration END), 2) AS trial_avg_duration,
ROUND(AVG(CASE WHEN activity_type = 'paid' THEN activity_duration END), 2) AS paid_avg_duration
FROM UserActivity
WHERE user_id IN (
SELECT DISTINCT user_id FROM UserActivity WHERE activity_type = 'free_trial'
) AND user_id IN (
SELECT DISTINCT user_id FROM UserActivity WHERE activity_type = 'paid'
)
GROUP BY user_id
ORDER BY user_id;