Fizz buzz

Math String Simulation

75.3% acceptance

Jan 13, 2026

3340

458

Given an integer n, return a string array answer (1-indexed) where: answer[i] == "FizzBuzz" if i is divisible by 3 and 5. answer[i] == "Fizz" if i is divisible by 3. answer[i] == "Buzz" if i is divisible by 5. answer[i] == i (as a string) if none of the above conditions are true.

Solution

Rust

Time O(1)

Space O(1)

LeetCode

solution.rs

impl Solution {
  pub fn fizz_buzz(n: i32) -> Vec<String> {
    (1..=n)
      .map(|i| {
        if i % 15 == 0 {
          "FizzBuzz".to_string()
        } else if i % 3 == 0 {
          "Fizz".to_string()
        } else if i % 5 == 0 {
          "Buzz".to_string()
        } else {
          i.to_string()
        }
      })
      .collect()
  }
}