#512
Easy Database Game play analysis ii
Database
54.6% acceptance
Mar 31, 2026
278
43
No description available.
Solution
Pandas
Time O(1)
Space O(1)
# Table: Activity
#
# +--------------+---------+
# | Column Name | Type |
# +--------------+---------+
# | player_id | int |
# | device_id | int |
# | event_date | date |
# | games_played | int |
# +--------------+---------+
# (player_id, event_date) is the primary key (combination of columns with unique values) of this table.
# This table shows the activity of players of some games.
# Each row is a record of a player who logged in and played a number of games (possibly 0) before logging out on someday using some device.
#
#
#
# Write a solution to report the device that is first logged in for each player.
#
# Return the result table in any order.
#
# The result format is in the following example.
#
# Example 1:
# Input:
# Activity table:
# +-----------+-----------+------------+--------------+
# | player_id | device_id | event_date | games_played |
# +-----------+-----------+------------+--------------+
# | 1 | 2 | 2016-03-01 | 5 |
# | 1 | 2 | 2016-05-02 | 6 |
# | 2 | 3 | 2017-06-25 | 1 |
# | 3 | 1 | 2016-03-02 | 0 |
# | 3 | 4 | 2018-07-03 | 5 |
# +-----------+-----------+------------+--------------+
# Output:
# +-----------+-----------+
# | player_id | device_id |
# +-----------+-----------+
# | 1 | 2 |
# | 2 | 3 |
# | 3 | 1 |
# +-----------+-----------+
import pandas as pd
def game_analysis(activity: pd.DataFrame) -> pd.DataFrame:
idx = activity.groupby('player_id')['event_date'].idxmin()
return activity.loc[idx, ['player_id', 'device_id']]