#706
Easy Algorithms Design hashmap
Array Hash Table Linked List Design Hash Function
66.4% acceptance
Feb 21, 2026
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Design a HashMap without using any built-in hash table libraries.
Implement the MyHashMap class:
MyHashMap() initializes the object with an empty map.
void put(int key, int value) inserts a (key, value) pair into the HashMap. If the key already exists in the map, update the corresponding value.
int get(int key) returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
void remove(key) removes the key and its corresponding value if the map contains the mapping for the key.
Solution
Rust
Time O(2^n)
Space O(n)
/*
* Design a HashMap without using any built-in hash table libraries.
* Implement the MyHashMap class:
* MyHashMap() initializes the object with an empty map.
* void put(int key, int value) inserts a (key, value) pair into the HashMap. If the key already exists in the map, update the corresponding value.
* int get(int key) returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
* void remove(key) removes the key and its corresponding value if the map contains the mapping for the key.
* Example 1:
* Input
* ["MyHashMap", "put", "put", "get", "get", "put", "get", "remove", "get"]
* [[], [1, 1], [2, 2], [1], [3], [2, 1], [2], [2], [2]]
* Output
* [null, null, null, 1, -1, null, 1, null, -1]
* Explanation
* MyHashMap myHashMap = new MyHashMap();
* myHashMap.put(1, 1); // The map is now [[1,1]]
* myHashMap.put(2, 2); // The map is now [[1,1], [2,2]]
* myHashMap.get(1); // return 1, The map is now [[1,1], [2,2]]
* myHashMap.get(3); // return -1 (i.e., not found), The map is now [[1,1], [2,2]]
* myHashMap.put(2, 1); // The map is now [[1,1], [2,1]] (i.e., update the existing value)
* myHashMap.get(2); // return 1, The map is now [[1,1], [2,1]]
* myHashMap.remove(2); // remove the mapping for 2, The map is now [[1,1]]
* myHashMap.get(2); // return -1 (i.e., not found), The map is now [[1,1]]
* Constraints:
* 0 <= key, value <= 106
* At most 104 calls will be made to put, get, and remove.
* struct MyHashMap {
* }
* /**
* * `&self` means the method takes an immutable reference.
* * If you need a mutable reference, change it to `&mut self` instead.
* */
* impl MyHashMap {
* fn new() -> Self {
* }
* fn put(&self, key: i32, value: i32) {
* }
* fn get(&self, key: i32) -> i32 {
* }
* fn remove(&self, key: i32) {
* }
* }
*/
struct MyHashMap {
data: Vec<i32>,
}
impl MyHashMap {
fn new() -> Self {
MyHashMap { data: vec![-1; 1_000_001] }
}
fn put(&mut self, key: i32, value: i32) {
self.data[key as usize] = value;
}
fn get(&self, key: i32) -> i32 {
self.data[key as usize]
}
fn remove(&mut self, key: i32) {
self.data[key as usize] = -1;
}
}