#771
Easy Algorithms Jewels and stones
Hash Table String
89.5% acceptance
Feb 21, 2026
5445
632
You're given strings jewels representing the types of stones that are jewels, and stones representing the stones you have. Each character in stones is a type of stone you have. You want to know how many of the stones you have are also jewels.
Letters are case sensitive, so "a" is considered a different type of stone from "A".
Solution
Rust
Time O(n)
Space O(1)
/*
* You're given strings jewels representing the types of stones that are jewels, and stones representing the stones you have. Each character in stones is a type of stone you have. You want to know how many of the stones you have are also jewels.
* Letters are case sensitive, so "a" is considered a different type of stone from "A".
* Example 1:
* Input: jewels = "aA", stones = "aAAbbbb"
* Output: 3
* Example 2:
* Input: jewels = "z", stones = "ZZ"
* Output: 0
* Constraints:
* 1 <= jewels.length, stones.length <= 50
* jewels and stones consist of only English letters.
* All the characters of jewels are unique.
*/
impl Solution {
pub fn num_jewels_in_stones(jewels: String, stones: String) -> i32 {
stones.chars().filter(|c| jewels.contains(*c)).count() as i32
}
}