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#833
Medium Algorithms

Find and replace in string

Array Hash Table String Sorting
50.9% acceptance
Feb 22, 2026
1244
1047
You are given a 0-indexed string s that you must perform k replacement operations on. The replacement operations are given as three 0-indexed parallel arrays, indices, sources, and targets, all of length k. To complete the ith replacement operation: Check if the substring sources[i] occurs at index indices[i] in the original string s. If it does not occur, do nothing. Otherwise if it does occur, replace that substring with targets[i]. For example, if s = "abcd", indices[i] = 0, sources[i] = "ab", and targets[i] = "eee", then the result of this replacement will be "eeecd". All replacement operations must occur simultaneously, meaning the replacement operations should not affect the indexing of each other. The testcases will be generated such that the replacements will not overlap. For example, a testcase with s = "abc", indices = [0, 1], and sources = ["ab","bc"] will not be generated because the "ab" and "bc" replacements overlap. Return the resulting string after performing all replacement operations on s. A substring is a contiguous sequence of characters in a string.

Solution

Rust
Time O(n log n)
Space O(1)
LeetCode
solution.rs
/*
 * You are given a 0-indexed string s that you must perform k replacement operations on. The replacement operations are given as three 0-indexed parallel arrays, indices, sources, and targets, all of length k.
 * To complete the ith replacement operation:
 * Check if the substring sources[i] occurs at index indices[i] in the original string s.
 * If it does not occur, do nothing.
 * Otherwise if it does occur, replace that substring with targets[i].
 * For example, if s = "abcd", indices[i] = 0, sources[i] = "ab", and targets[i] = "eee", then the result of this replacement will be "eeecd".
 * All replacement operations must occur simultaneously, meaning the replacement operations should not affect the indexing of each other. The testcases will be generated such that the replacements will not overlap.
 * For example, a testcase with s = "abc", indices = [0, 1], and sources = ["ab","bc"] will not be generated because the "ab" and "bc" replacements overlap.
 * Return the resulting string after performing all replacement operations on s.
 * A substring is a contiguous sequence of characters in a string.
 * Example 1:
 * Input: s = "abcd", indices = [0, 2], sources = ["a", "cd"], targets = ["eee", "ffff"]
 * Output: "eeebffff"
 * Explanation:
 * "a" occurs at index 0 in s, so we replace it with "eee".
 * "cd" occurs at index 2 in s, so we replace it with "ffff".
 * Example 2:
 * Input: s = "abcd", indices = [0, 2], sources = ["ab","ec"], targets = ["eee","ffff"]
 * Output: "eeecd"
 * Explanation:
 * "ab" occurs at index 0 in s, so we replace it with "eee".
 * "ec" does not occur at index 2 in s, so we do nothing.
 * Constraints:
 * 1 <= s.length <= 1000
 * k == indices.length == sources.length == targets.length
 * 1 <= k <= 100
 * 0 <= indexes[i] < s.length
 * 1 <= sources[i].length, targets[i].length <= 50
 * s consists of only lowercase English letters.
 * sources[i] and targets[i] consist of only lowercase English letters.
 */

impl Solution {
  pub fn find_replace_string(s: String, indices: Vec<i32>, sources: Vec<String>, targets: Vec<String>) -> String {
    let s_bytes = s.as_bytes();
    // Pre-check each op against the original string; collect only matching ones
    let mut ops: Vec<(usize, &str, &str)> = indices.iter()
      .zip(sources.iter())
      .zip(targets.iter())
      .filter_map(|((&i, src), tgt)| {
        let idx = i as usize;
        if s_bytes[idx..].starts_with(src.as_bytes()) {
          Some((idx, src.as_str(), tgt.as_str()))
        } else {
          None
        }
      })
      .collect();
    // Sort by index descending so we can replace without shifting
    ops.sort_by(|a, b| b.0.cmp(&a.0));
    let mut result = s;
    for (idx, src, tgt) in ops {
      result = format!("{}{}{}", &result[..idx], tgt, &result[idx+src.len()..]);
    }
    result
  }
}