#988
Medium Algorithms Smallest string starting from leaf
String Backtracking Tree Depth-First Search Binary Tree
61.1% acceptance
Feb 27, 2026
2409
336
You are given the root of a binary tree where each node has a value in the range [0, 25] representing the letters 'a' to 'z'.
Return the lexicographically smallest string that starts at a leaf of this tree and ends at the root.
As a reminder, any shorter prefix of a string is lexicographically smaller.
For example, "ab" is lexicographically smaller than "aba".
A leaf of a node is a node that has no children.
Solution
Rust
Time O(n)
Space O(n)
// Definition for a binary tree node.
// #[derive(Debug, PartialEq, Eq)]
// pub struct TreeNode {
// pub val: i32,
// pub left: Option<Rc<RefCell<TreeNode>>>,
// pub right: Option<Rc<RefCell<TreeNode>>>,
// }
//
// impl TreeNode {
// #[inline]
// pub fn new(val: i32) -> Self {
// TreeNode {
// val,
// left: None,
// right: None
// }
// }
// }
use std::rc::Rc;
use std::cell::RefCell;
impl Solution {
pub fn smallest_from_leaf(root: Option<std::rc::Rc<std::cell::RefCell<TreeNode>>>) -> String {
let mut best = String::new();
fn dfs(node: &Option<std::rc::Rc<std::cell::RefCell<TreeNode>>>, path: &mut Vec<u8>, best: &mut String) {
if let Some(n) = node {
let n = n.borrow();
path.push(b'a' + n.val as u8);
if n.left.is_none() && n.right.is_none() {
let s: String = path.iter().rev().map(|&c| c as char).collect();
if best.is_empty() || s < *best { *best = s; }
}
dfs(&n.left, path, best);
dfs(&n.right, path, best);
path.pop();
}
}
dfs(&root, &mut Vec::new(), &mut best);
best
}
}